Tricks to Solve Percentage Questions (Important Facts and Formula) for Bank, SSC, Railway and Other Government Job related Competitive Exam. Percentage questions are commonly asked in all the Competitive Exam. In this Article we will Discuss some Tricks to Solve Percentage Questions Quickly.
1. Concept of Percentage : By a certain
percent ,we mean that many hundredths. Thus x percent means x hundredths,
written as x%.
To
express x% as a fraction : We have , x% = x/100.
Thus, 20%
=20/100 =1/5; 48% =48/100 =12/25, etc.
To
express a/b as a percent : We have, a/b
=((a/b)*100)%.
Thus, ¼ =[(1/4)*100] = 25%; 0.6 =6/10 =3/5 =[(3/5)*100]%
=60%.
2. If the price of a commodity increases by R%, then the
reduction in consumption so as not to increase the expenditure is [R/(100+R))*100]%.
If the price of the commodity decreases by R%,then the increase in consumption so as to decrease the expenditure is [(R/(100-R)*100]%.
If the price of the commodity decreases by R%,then the increase in consumption so as to decrease the expenditure is [(R/(100-R)*100]%.
3. Results on Population : Let
the population of the town be P now and suppose it increases at the rate
of R% per annum, then :
1. Population after n years = P [1+(R/100)]^n.
2. Population n years ago = P /[1+(R/100)]^n.
4. Results on Depreciation : Let
the present value of a machine be P. Suppose it depreciates at the
rate R% per annum. Then,
1. Value of the machine after n years = P[1-(R/100)]n.
2. Value of the machine n years ago = P/[1-(R/100)]n
5. If A is R% more than B, then B is less than A by [(R/(100+R))*100]%.
If A is R%
less than B , then B is more than A by [(R/(100-R))*100]%
6. Decimal to Fraction Percentage: Remember this
table for faster Calculation. Specially in Data Interpretation where percentage
is one of the major part.By remembering these fraction you can do calculation
fast.
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